-16x^2+40x+0=9

Solution for -16x^2+40x+0=9 equation:

-16x^2+40x+0=9

We move all terms to the left:

-16x^2+40x+0-(9)=0

We add all the numbers together, and all the variables

-16x^2+40x-9=0

a = -16; b = 40; c = -9;
Δ = b2-4ac
Δ = 402-4·(-16)·(-9)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-32}{2*-16}=\frac{-72}{-32}
=2+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+32}{2*-16}=\frac{-8}{-32}
=1/4
$